3(2y^2+y+3)=0

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Solution for 3(2y^2+y+3)=0 equation: 



3(2y^2+y+3)=0

We multiply parentheses

6y^2+3y+9=0

a = 6; b = 3; c = +9;
Δ = b2-4ac
Δ = 32-4·6·9
Δ = -207
Delta is less than zero, so there is no solution for the equation

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